Lock-combination Problem Of Permutation-combination Math Problem- Permutations: Combination Lock?
Math problem- permutations: combination lock? - lock-combination problem of permutation-combination
A combination lock is opened when the correct choice of three numbers (1-40, is selected included). How many different combinations are possible barriers?
The answer is 64000, but when I plug into the computer as is 4P3 59,280. What am I doing wrong?
I have tried to do is possible even 40 x 39 x 38 (the first three questions), and then I have 59,280.
Moreover, what is integration?
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2 comments:
Inclusive means that all numbers are used by 1 to 40 (including 1 and 40).
It uses permutations here because the numbers can be repeated (15 15 15 is a valid combination).
40 options for the first issue
40 options for the second question
40 options for the third edition
40 × 40 × 40 = 64000
If numbers do not need to be repeated, for 40 × 39 × 38 = P (40.3 been)
Then asked if the issue is not whether a repetition make it possible, and usually a repetition of the block number, therefore, allows for any choice of the number 40th Therefore, and this gives the answer of 40 ^ 3 = 64, 000
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